How much work must be done to a truck of mass 3580 kg to accelerate from 21m/s to 24.6m.s

Answer 1

The work done is the change in kinetic energy.

W = ΔK = mv₂²/2 - mv₁²/2 = (m/2)(v₂² - v₁²)

m = 3580 kg

v₁ = 21 m/s

v₂ = 24.6 m/s

Just plug in the numbers and get W in joules.