How long will it take for a basketball to fall from a height of 2.7 m?

Answer 1

The equation for this is as follows:

Δx = V_1t *1/2 * a * t²

Since V₁ , the initial velocity, is 0, the equation becomes:

Δx = 1/2 * a * t²

Δx is the distance, a is the acceleration of gravity, and t is the time. We substitute out values into the equation and we have:

2.7 m - 1/2 * 9.8 m/s² * t² (solve for t)

2.7m /4.9m/s² = t² (meters will cancel out, leaving s²)

0.74 s= t

Answer 2

If you neglect air resistance, you can use

h = gt²/2 ⇒

t = √(2h/g)

Plug in

h = 2.7 m

g = 9.8 m/s²

and get t in seconds.