An emergency supply kit is dropped from a military helicopter but the kit can only handle an impact of 61.9 m/s. How far from the ground can the helicopter be without risking that the kit breaks?

Answer 1

The velocity of a dropped object is sqrt(2*g*h) where g = gravity constant, & h = height

so v² = 2*g*h and h = v²/2*g = (61 m/s)²/(2*9.81 m/s²) = 195.3 meters