The quadratic function: y = k (x – 2)^2 has a turning point of (2,0). Calculate the value of k algebraically.

Answer 1

turning point is where slope = 0

y' = (2k(x-2)^2)' = 2k where k = any real number, except 0

if (2,0) is the turning point it's the vertex = extremum (min or max)

k could be anything except 0

k just determines how flat or vertical the parabola is, whether upward or downward opening