A 0.600 kg particle has a velocity of 2.00 m/s at point A and a kinetic energy of 7.50 J at B.

Question

(a) What is your kinetic energy at point A?

(b) Its velocity in B?

(c) The total work done on the particle when it moves from point A to point B?

Answer 1

(a)

K_A = mv_A²/2 = (0.600)(2.00)²/2 J = ? J

(b)

v_B = √(2K_B/m) = √[2(7.50)/0.600] m/s = ? m/s

(c)

W_A→B = K_B - K_A

Plug in the numbers.