How would I set up a triangle given both a sine and a cosine?

Question

Given sin A= 24/25, A lies in quadrant 2, and cos B= 2/5, B lies in Quadrant 1, how would I sketch a triangle that would apply to both of these requirements?

I have to then use this triangle to solve a difference of cosine and a double angle problem but that should be fine as long as I can actually set up the triangle.

Answer 1

sin A = 24/25 → cos A = -3√11

sin B = 2/5 → cos B = √21

That's is all that is needed for the difference and double formulas.