
Benjamin T. answered 01/08/25
Physics Professor, and Former Math Department Head
For this pipe I will assume it is open at one end and closed at the other. To see how waves fit in pipes consider this gif.
https://www.acs.psu.edu/drussell/demos/standingwaves/standing.gif
What is the wavelength of its fundamental vibration?
The fundamental vibration has the longest wavelength. 1/4 of the wave length will fit in the pipe. This will have a node at the closed end for particle displacement and an antinode at the open end of the pipe.
L = 0.84m
L = 1/4 λ
λ = 4 (0.84 m) = 3.36 m
What is the frequency of its fundamental vibration.
v = λ f, where v = 343 m/s (the speed of sound).
f = (343 m/s )/(3.36 m) = 102.1 Hz
What is the frequency of the first overtone?
What is the frequency of the third overtone.
These would be the next waves that can fit in the pipe.
L = 1/4 λ, 3/4 λ, 5/4 λ, ... (2n-1)/4 λ
λ = 4 L/ (2n-1)
v = λ f
f = v (2n-1)/(4 L)
n = 2, f = 306.3 Hz
n = 4, f = 714.6 Hz
What is the frequency of the third harmonic?
The third harmonic is the same as the second overtone.
n = 3, f = 510.4 Hz