 
Arturo O. answered  11/23/19
Experienced Physics Teacher for Physics Tutoring
This is a kinematics problem. Use the relation
v22 - v12 = 2ad
v1 = initial speed = 15 m/s
v2 = final speed = 0 (full stop)
d = distance required for speed to drop from v1 to v2
a = acceleration (which in this situation, is negative)
a = F/m = -μkmg / m = -μkg
μk = coefficient of kinetic friction = 0.67
Put it all together and get
v12 = 2(μkg)d ⇒
d = v12 / (2μkg)
Now plug in the given values of v1, μk, and g, and get d in meters.
 
     
             
                     
                    