Circular motion question

Question

An object of mass m moves in a circular path at constant speed v. The centripetal force on the object is F. If the object had double the mass and 1/4 the speed then what would the magnitude of the centripetal force on the object be? answer in terms of F.

Answer 1

The centripetal force F = mv²/r, where m is mass, v is speed and r = radius

If the mass of the object is double and the speed is 1/4^th, then the new centripetal force is

F_new = 2m(1/4v)²/r = (2/16)mv²/r =(1/8)F