Anna S.

asked • 11/20/19

Physics Question

The distance between two point charges q1 = 7.5⋅10-9 C and q2 = -14.7⋅10-9 C is 5 cm.Calculate the intensity of the electric at the point that is 3 cm from the positive charge and 4 cm from the negative charge.

Anand M.

An important word seems to be missing, what electric quantity is requested? Field or potential?
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11/20/19

Timothy D.

tutor
I believe they're looking for the electric field, and also we don't know where the points are located as well, let me look in my physics II textbook, perhaps I can find an example that looks the same.
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11/20/19

Anand M.

The distances give enough information to describe the geometry. I'll agree that it is probably asking for electric field, because "intensity" suggests the magnitude of a vector quantity.
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11/20/19

Timothy D.

tutor
I'll take a wack at it. I just see a 3,4,5 triangle, with the test charge or point on the vertice where the right angle exists. q2 is above 4 cm, and q1 to the left 3 cm
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11/20/19

Anand M.

I'll have to try the video answer idea! I would have had the q_1 to q_2 line on the x-axis, your arrangement makes the problem much easier to understand.
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11/20/19

Timothy D.

tutor
Thank you, I appreciate that
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11/21/19

1 Expert Answer

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Timothy D. answered • 11/20/19

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