
John B. answered 01/26/15
Tutor
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BS CHEMISTRY and BS MATHEMATICS TUTOR - NORTH ATLANTA / ONLINE
It may be easier to demonstrate since you have done it before. Here are a few examples:
The sign before the constant n determines whether the factors are both positive, both negative, or opposite in sign.
Factor: x2 + bx + n: Find factors of n which are both positive and add to equal b.
Factor: x2 + bx - n: Find factors of n. One is positive and one is negative. These add to equal b.
Factor: x2 - bx + n: Find factors of n which are both negative and add to equal b.
Factor: x2 - bx - n: Find factors of n. One is positive and one is negative. These add to equal b.
x2 + 6x + 9 Factors of 9: 1,3,9 3+3=9 both factors are 3. (x+3)(x+3) is the factored form
x2 + 9x + 20 Factors of 20: 1,2,4,5,10,20 5+4=9 (x+4)(x+5) is the factored form
x2 + 1x - 6 Factors of 6: 1,2,3,6 3-2=1 (x+3)(x-2) is the factored form
x2 -2x - 8 Factors of 8: 1,2,4,8 2-4= -2 (x+2)(x-4) is the factored form
x2 + 2x - 3 Factors of 3: 1,3 3-1=2 (x+3)(x-1) is the factored form
x2 - 10x - 24 Factors of 24: 1,2,3,4,6,8,12 12-2=10 (x+12)(x-2) is the factored form
x2 + 8x + 16 Factors of 16: 1,2,4 4+4=8 (x+4)(x+4) is the factored form
x2 - 2x - 35 Factors of 35: 1,5,7 7-5=2 (x+5)(x-2) is the factored form