In the interval: 0less than equal to theta less than 360, what values of theta will satisfy the equation: 4sin^2 theta + 4 cos theta - 5 =0

Answer 1

4sin²θ + 4cosθ - 5 = 0

4(1 - cos²θ) + 4cosθ - 5 = 0

4cos²θ - 4cosθ + 1 = 0

(2cosθ - 1)² = 0

cosθ = 1/2

θ = 60° or 300°