Physics Problem on drag

Question

Two flying squirrels glide through the air. Squirrel 1 has twice the cross-section area of squirrel 2, but squirrel 2 is going twice as fast. How do the drag forces experienced by the squirrels, |Fdrag1| and |Fdrag2|, compare (assuming they have the same drag coefficient)?

a) |Fdrag1| = |Fdrag2|

b) |Fdrag1| = 2|Fdrag2|

c) |Frdag1| = 4|Fdrag2|

d) |Fdrag1| = |Fdrag2|/2

e) |Fdrag1| = |Fdrag2|/4

Answer 1

F = AC_Dρv²/2

F₁ = A₁C_Dρv₁²/2

F₂ = A₂C_Dρv₂²/2

A₁ = 2A₂

v₂ = 2v₁ ⇒ v₁ = v₂/2

F₁ = (2A₂)C_Dρ(v₂/2)²/2 = (1/2)(A₂C_Dρv₂²/2) = F₂/2

F₁ = F₂/2

Answer (d) is correct.