Physics- Work/ Energy

Question

Michael uses his bike to apply 407 N to himself and the bike by pedaling as he approaches a 1.5 m tall ramp which is 7.4 m away. He starts from rest to accomplish this feat. How fast will he be moving just before he hits the ramp? (Mike and the bike have a combined mass of 141 kg)

Answer 1

Work = F*d = change in kinetic energy which makes since, if you push something with a force along a distance, it's gonna start moving faster

initial kinetic energy is zero so change in kinetic energy is .5*m*v² (cuz change is final - initial but intial is zero so its just .5*m*V_final²)

407N * 7.4m = 0.5 * (141 kg) * v² so just solve for v. Note: work is in units joules, so is kinetic energy, and F*d gives you N-m (Newton-meters) which is therefore equivalent to joules.