Magnitude of the torque the loop experiences

Question

A circular wire loop of 28 turns and radius 2.18 cm carries a current of 1.25 A in a magnetic field of 0.250 T. If the plane of the loop is oriented parallel to the field, what is the magnitude of the torque the loop experiences due to the field?

Answer 1

use the equation that torque Τ= NABIsinθ. In this problem N=28 A=π(2.18x10^-2)² B= .25 tesla I= 1.25 amp θ =90º. using these numbers T = 28•14.93x10^-4•.25•sin90°•1.25 N-m and T= 130.6x10^-4 N-m = .0131 N-m.