Arturo O. answered 11/03/19
Experienced Physics Teacher for Physics Tutoring
Just do a dimensional analysis.
volt = henry amp / sec ⇒
henry = volt sec / amp = volt sec / (coul / sec) = volt sec2 / coul
Answer (b) is correct.
Brandon Y.
asked 11/03/19Using the equation ε = −L ΔI / Δt, it can be shown that a Henry is equivalent to a
a. VA/s
b. Vs^2/C.
c. VC/s
d. V/A
Arturo O. answered 11/03/19
Experienced Physics Teacher for Physics Tutoring
Just do a dimensional analysis.
volt = henry amp / sec ⇒
henry = volt sec / amp = volt sec / (coul / sec) = volt sec2 / coul
Answer (b) is correct.
Mark H. answered 11/03/19
Tutoring in Math and Science at all levels
You mean V = L * ΔI / Δt
put in the units:
volts = L * amps / seconds
rearrange:
L = volts*seconds / amps
If one of the answers involves coulombs, then replace amps with coulombs/sec
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