Howard J. answered 11/03/19
Principal Mech Engr with 35+ years' on-the-job physics experience
A youngster shoots a bottle cap up a 22.0o inclined board at 1.97 m/s. The cap slides in a straight line, slowing to 1.03 m/s after traveling some distance.
If the coefficient of kinetic friction is 0.36, find that distance.
Let D=the unknown distance, then the elevation gained is Dsin22
Initially,
KEi=0.5m(1.97)2=1.94m
PEi=0
Finally,
KEf=0.5m(1.03)2=0.53m
PEf=mgDsin(22)
The work W done by friction is the normal force times the coefficient of friction:
W=0.36mgDcos(22)
Energy Balance
Initial Energy-Work=Final Energy
KEi+PEi-W=KEf+PEf
KEi+0-W=KEf+PEf
1.94m-0.36mgDcos(22)=0.53m+mgDsin(22)
1.94-0.36gDcos(22)=0.53+gDsin(22)
1.94-0.53=gD[sin(22)+0.36cos(22)]
D=(1.94-0.53)/[9.81(0.375+0.36(0.927)]=0.20 m
Note solution does not depend on mass!