Jane A. answered 10/31/19
Experienced Ivy League Math tutor - Patient & Knowledgeable!
#1: (tan3(x)-sec2(x)tan(x))/(cot(-x))
= (tan3(x)-sec2(x)tan(x))(-tan(x)) By cot (-x) = - tan (x) and by 1/cot x = tan x
= sec2(x)tan2 (x) – tan4(x) By distribution of -tan (x)
= tan2 (x) (sec2(x)- tan2 (x)) Pull out common tan2 (x)
= tan2 (x) (1 + tan2 (x) - tan2 (x)) By substitution of sec2(x) = 1 + tan2 (x)
= tan2 (x)
#2: 1-(sec2(x)/tan2(x))
= 1 – ((1 - tan2(x))/ tan2(x)) By sec2 (x) = 1- tan2 (x)
= 1 – (1/ tan2(x)) – 1
= - 1/tan2(x)
= - cot (x)
#3: sin(x)+(cos2(x)/sin(x))
= sin x ( 1 +(cos2(x)/sin2(x)) )
= sin(x) (1 + cot2(x))
= sin (x) csc2(x) By (1 + cot2(x)) = csc2(x)
= sin (x)/ sin2(x) By csc2(x) = 1/sin2(x)
= 1/ sin(x)
= csc (x)