Lilla H. answered 10/24/19
Very Patient Finite Math Tutor with 20+ Years of Teaching
(a) A includes the factors 1,2,3 and 4. So n(A)=4,
B includes the factors 3,4, 5 and 6. So n(B) = 4
C includes the factors 3, 4, 5, 6, 7 and 8. So n(C)= 6
(b) A ∩ B includes the common members of A and B: 3, 4 So n(A ∩ B) = 2
(c) Ac includes 5, 6, 7 and 8; Ac ∩ C ={ 5, 6, 7, 8} n(Ac ∩ C)=4
(d) Bc = { 1, 2, 7, 8} A ∩ Bc={ 7 ,8} So n(A ∩ Bc)= 2