Mark M. answered 10/23/19
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Mathematics Teacher - NCLB Highly Qualified
Consider first:
Zeros are ±4, and 9.
(v + 4)2 > 0
Since the 3 is negative the following must be true
v - 4 > 0 and v - 9 < 0
v > 4 and v < 9, this is possible.
or
v - 4 < 0 and y - 9 > 0
v < 4 and v > 9, this is not possible
-4 ∪ [4, 9]