Vanessa E.

asked • 10/23/19

A 1500 kg car heading west slams on brakes

A. What would the frictional force be to stop the car on a sunny day ?

Arturo O.

There is not sufficient information in the problem statement to answer the question.
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10/23/19

Steven C.

You don't quite have enough information - however my guess is that for this class you're given a reference table! It turns out that the coefficients of friction and known, previously measured, values. http://www.p12.nysed.gov/assessment/reftable/physics-rt/physics06tbl.pdf For instance, the New York Regents reference table has specific values for different materials that may be in contact. Using this, and assuming a horizontal road we can use our equation Ff = uFn
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10/23/19

1 Expert Answer

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Peter K. answered • 10/26/19

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The friction force (on a level road) will be equal to the coefficient of friction between the tires and the road (probably somewhere between 0.7 and 0.8) times the normal force (mass x g): Ff = mu X mass X g


The coefficient of friction is a measured quantity for every pair of unique surfaces. I believe that tires must have a minimum coefficient of friction of 0.7 on typical road surfaces, but you may want to use a figure that your teacher has used in similar problems.

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