Mark M. answered 10/18/19
Mathematics Teacher - NCLB Highly Qualified
Yes, the zeros are -2, 2, and 12
For the product to be greater than zero, i.e., positive
y - 2 and y - 12 must be positive.
Y must be greater than 2 and 12,
(12, +∞)
Vanessa C.
asked 10/18/19−7(y−2)(y+2)^2(y−12) ≥ 0
Mark M. answered 10/18/19
Mathematics Teacher - NCLB Highly Qualified
Yes, the zeros are -2, 2, and 12
For the product to be greater than zero, i.e., positive
y - 2 and y - 12 must be positive.
Y must be greater than 2 and 12,
(12, +∞)
Patrick B. answered 10/18/19
Math and computer tutor/teacher
the function is zero at -2,2 and 12
interval (-infinty,-2) the function is negative
interval (-2,2) the function is negative
interval (2,12) the function is positive
interval (12,infinity) the function is negative
the solution set is {2} U [2,12]
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