Mark M. answered • 10/16/19
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tan θ = 1, θ = 45°
For -180º < θ -90° θ = 225°
tan (225/2) = -√[(1 - cos 225) / (1 + cos 225)]
Addie D.
asked • 10/16/19Find the exact value of tan (theta/2) for tantheta=1
Please help!
given conditions: -180*<theta<-90*
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