The period of rotation of Mercury in hours is 1407.6 hr. Given that Mercury has a radius of 24 X 10^6 m at its equator, what is the linear velocity (in m/s) at Venus's surface?

Answer 1

T = period

R = radius

v = 2πR/T

You know R in meters. You know T in hours. Convert T to seconds, plug the numbers into

v = 2πR/T

and get v in meters/sec.