solve vertical and horizontal forces for 40n at 20 degrees

Answer 1

Draw the diagram for the problem using the known quantities, Force, F = 40 N and, angle, θ = 20°

The vertical component is F_y = Fsin(θ) = 40sin(20°) = 13.7 N and

The horizontal component is F_x = Fcos(θ) = 40cos(20°) = 37.6 N