AR U. answered • 12d

Experienced Phyiscs and Math Tutor

The basket ball player spends 0.4s going up and the other 0.4s coming down, therefore the time, t = 0.4s

Using

s = v_{i}t + (1/2)at^{2}

where the initial speed, v_{i } = 0 m/s, the acceleration, a = g = 9.81m/s^{2} [since governed by free fall motion]

Therefore,

s = .5(9.81ms/^{2})(.4s)^{2} = 0.78m as the height attained by the basket ball player when she jumped.