a basketball player jumped straight up to grab a rebound. if she was in the air for .8 seconds how high did she jump

Answer 1

The basket ball player spends 0.4s going up and the other 0.4s coming down, therefore the time, t = 0.4s

Using

s = v_it + (1/2)at²

where the initial speed, v_i = 0 m/s, the acceleration, a = g = 9.81m/s² [since governed by free fall motion]

Therefore,

s = .5(9.81ms/²)(.4s)² = 0.78m as the height attained by the basket ball player when she jumped.