Mark M. answered 10/09/19
Retired math prof. Very extensive Precalculus tutoring experience.
Assuming that the polynomial has real coefficients, complex roots occur in conjugate pairs. So, since 3 - i is a root, so is 3 + i.
A polynomial with the given roots is (x + 2)[x - (3-i)][x - (3+i)]
= (x + 2){(x-3) + i][(x-3) - i] = (x + 2)[(x-3)2 - i2]
= (x + 2)(x2 - 6x + 10) = x3 - 6x2 + 10x + 2x2 - 12x + 20 = x3 - 4x2 - 2x + 20