
TrungThanh B. answered 10/26/19
Math and Science Tutor
let's call vertical component of distance Δy, and we have
Δy = v0t + (1/2)at2
159 = (0)t + (1/2)(9.8)t2
t = 5.7 sec
Let's call horizontal component of distance Δx, and we have
(5.7s)(39 m/s) = 2.2 x 102 m
The package will strike at a point 2.2 x 102 m away from its initial drop