Logan D. answered 01/21/15
Tutor
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Expert Teacher: Calculus, Differential Equations & Physics for Success
We can break the trip into three parts, calculate them, then add them up for the first part of the question. For the second part, we can use our newly found distance to get the average speed.
a) How far did you travel on this trip?
Trip 1:
r = 65.0 mph
t = 2.84 hours
r = d / t
⇒ d = rt = (65.0 mph)(2.84 hours) = 184.6 mi
Trip 2:
r = 0 mph
t = 28.5 min = 0.475 hours
d = rt = (0 mph)(0.475 hours) = 0 mi
Trip 3:
r = 54.8 mph
t = 1.70 hours
d = rt = (54.8 mph)(1.70 hours) = 93.16 mi
Total distance = Trip 1 + Trip 2 + Trip 3
= 184.6 mi + 0 mi + 93.16 mi = 277.76 mi
b) What was your average speed?
dTOT = 277.76 mi
tTOT = 2.84 hours + 0.475 hours + 1.70 hours = 5.015 hours
tTOT = 2.84 hours + 0.475 hours + 1.70 hours = 5.015 hours
r = d / t = (277.76 mi) / (5.015 hours)
= 55.385 mph