
Patrick B. answered 10/01/19
Math and computer tutor/teacher
C = sqrt( A^2 + B^2) where A is the distance of the sideline and B is the distance of the 50 yard line
dC/dT = (1/2) * (2A dA/dt + 2B dB/dT) / sqrt( A^2 + B^2)
= (A dA/dt + B dB/dT) / sqrt( A^2 + B^2)
when A =20, then t=5 and B=15.
so the derivative is (20*4 + 15*3)/ sqrt( 20^2+15^2)
= (180+45)/ sqrt( 400+225)
= 225/sqrt(625)
= 225/25
= 9

Richard P.
10/01/19