how do I find the total cost of four years’ worthof tuition after the tenth year (11thto 14thyear).

Question

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

double initialTuition = 10000;

double theRate = 0.05;

double startOfFourYearTuition = initialTuition;

double totalTuition;

for (int i = 1; i < 11; i++) {

initialTuition = ((theRate * initialTuition) + initialTuition);

cout << "Tuition after " << i << " years is " << initialTuition;

cout << endl;

while (i == 11){

cout << "Tuition after " << i << " years is " << initialTuition;

cout << endl;

break;

}

while ((i > 11) && (i < 15)) {

totalTuition += initialTuition;

}

}

cout << "\nThe four-year tuition after ten years is " << totalTuition;

cout << endl;

return 0;

}

my output:

Tuition after 1 years is 10500

Tuition after 2 years is 11025

Tuition after 3 years is 11576.2

Tuition after 4 years is 12155.1

Tuition after 5 years is 12762.8

Tuition after 6 years is 13401

Tuition after 7 years is 14071

Tuition after 8 years is 14774.6

Tuition after 9 years is 15513.3

Tuition after 10 years is 16288.9

The four-year tuition after ten years is 2.05181e-307

expected output:

Tuition after 1 years is 10500

Tuition after 2 years is 11025

Tuition after 3 years is 11576.2

Tuition after 4 years is 12155.1

Tuition after 5 years is 12762.8

Tuition after 6 years is 13401

Tuition after 7 years is 14071

Tuition after 8 years is 14774.6

Tuition after 9 years is 15513.3

Tuition after 10 years is 16288.9

The four-year tuition after ten years is 73717.8

Answer 1

Use the formula P*(1+r)^t where P=1000 r = 0.05 and t=10

the 16288.94 figure is correct !!!

You only need one for loop!!!!

If you must display in annually in a table then here is some code:

using namespace std;

#include <iostream>

#include <iomanip>

#include <math.h>

int main()

{

double newPrincipal;

double P;

double rate = 0.05;

double interestEarned;

double Principal=10000;

int t=10;

P = Principal;

cout << "Year Starting Principal interest Earned new Principal " << endl;

for (int iLoop=1; iLoop<=t; iLoop++)

{

interestEarned = Principal*rate;

newPrincipal = Principal + interestEarned;

//pardon the white space; otherwise use std::setwidth()

cout << iLoop << " " << std::setprecision(2) << std::fixed << Principal

<< " " << std::setprecision(2) << std::fixed << interestEarned

<< " " << std::setprecision(2) << std::fixed << newPrincipal << endl;

Principal = newPrincipal;

}

cout << "shortcut formula says: " << P*pow(1+rate,t) << endl;

}