
Yefim S. answered 09/28/19
Math Tutor with Experience
m2g - T = m2a
T - m1gsinθ - µm1gcosθ = m1a
T is tension in rope, g = 9.8m/s^2 accelaration of gravty,
µ - coefficient of kinetic friction,
If we add these equations we get: g(m2 - m1sinθ - μm1cosθ) = (m1+m2)a
from here accelaration a = g(m2 - m1sinθ - μm1cosθ)/(m1+m2)
a = 9.8m/s^2(6kg - 6kgsin29°- 0.15•6kgcos29°)/(6kg + 6kg) ≅ 1.88m/s^2