Scott D. answered 09/23/19
Physics Teacher with Many Years Experience, Including AP-Physics
a = Fnet / m. Fnet is the horizontal force. Also, weight is 203 N = mg, so m = 203 N / 10 m/s2.= 20.3 kg. Now we can get a = 55 N / 20.3 kg = 2.7 m/s2.
Kristyn B.
asked 09/20/19A child sitting on a sled is pulled by a rope along a frictionless surface. The child and the sled weigh 203 N and the horizontal force on the sled is 55 N. What is the acceleration of child and sled?
Scott D. answered 09/23/19
Physics Teacher with Many Years Experience, Including AP-Physics
a = Fnet / m. Fnet is the horizontal force. Also, weight is 203 N = mg, so m = 203 N / 10 m/s2.= 20.3 kg. Now we can get a = 55 N / 20.3 kg = 2.7 m/s2.
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