Pre-Calculus....

Question

Determine the equation of the quadratic function with vertex (1,3) and passing through the point (-2,-24).

Answer 1

The vertex form of the function is y = a(x - h)² + k, where (h,k) is the vertex.

So, we have y = a(x - 1)² + 3

Since (-2, -24) is on the graph, -24 = 9a + 3

9a = -27

a = -3

Equation: y = -3(x - 1)² + 3

Answer 2

Here's a little help to get you started.

y=ax^2+bx+c

You already have two points on the graph. One equation becomes

3=a+b+c. Figure out the other. Then also use the information that (1,3) is the vertex.