The length of the line from the 2 points is sqrt{ (-3-7)2 + (8-6)2 } = 10.2
So, the radius of the circle is 10.2/2 = 5.1
The midpoint of the line joining the points is (2,7). So the equation of the circle is
(x-2)2 + (y-7)2 = (5.1)2 = 26
Jacob G.
asked 09/18/19Find the equation of a circle in standard form where C(-3,8) and D(7,6) are endpoints of a diameter.
The length of the line from the 2 points is sqrt{ (-3-7)2 + (8-6)2 } = 10.2
So, the radius of the circle is 10.2/2 = 5.1
The midpoint of the line joining the points is (2,7). So the equation of the circle is
(x-2)2 + (y-7)2 = (5.1)2 = 26
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