A cannonball is launched horizontally off a 70 m high castle wall with a speed of 50 m/s. How long will the cannonball be in the air before striking the ground?

Answer 1

Use the equation 70 =0 -at²/2 where v_0y =0 and v_0x = 50m/s so now 70= 9.8t²/2 70=4.9t² and t² = 14.29s². Taking the square root gives t= 3.78s for time in the air before hitting the ground.