A 0.75 kg ball of clay is thrown at the wall at a speed of 12 m/s (which after it sticks). It takes 0.1 seconds for the ball to come to a complete stop. What is the deceleration of the ball?

Answer 1

Velocity went from 12 m/s to 0 in

0.1 seconds.

Therefore acceleration = change in velocity/(interval of time)

a = (12 m/s)/0.1 s

a = 120 m/s/s