Use an algebraic approach to solve the problem.

Question

Aura took three biology exams and has an average score of 89. Her second exam score was 10 points better than her first, and her third exam score was 4 points better than her second exam. What were her three exam scores?

(Lowest score) ______

______

(Highest score) ______

Answer 1

1st score = x

2nd score = 10 + x

3rd score = 4 + (10 + x)

average = 89 = (1st score + 2nd score + 3rd score) / 3

89 = (x + 10 + x + 4 + 10 + x)/3 = (3x + 24)/3

89 = x + 8

x = 89-8 = 81

1st score = x = 81

2nd score = 10 + x = 10 + 81 = 91

3rd score = 4 + (10 + x) = 14 + 81 = 95