
David S. answered 09/15/19
Experienced AP/College Physics Teacher and Tutor
Newton's Law of Universal Gravitation states that the magnitude of the gravitational force between ANY two objects that have mass is given by the relationship...
|FG| = Gm1m2/r2 where G = 6.67x10-11 and r is the distance between the centers of mass of the two objects.
a) We just have to substitute the masses and distance given into the above equation and solve. Don't forget to include the direction, which is "toward the Earth".
b) According to Newton's Third Law of Motion, the force of the Moon on the Earth and the force of the Earth on the Moon are equal in magnitude and opposite in direction. Therefore, the answer to b is the same number as the answer to a, only in the opposite direction (or "toward the Moon").
c) Here, we're using the equation above for two different situations, the force of the Earth on the Moon (at some unknown distance) and the force of the Earth on the student near the Earth's surface. So, we can set the two equal to each other.
GmEarthmMoon/r12 = GmEarthmstudent/r22 where r1 is the distance we're looking for (distance between Earth and Moon after moving it so that the forces are equal) and r2 is the distance between the Earth and the student, which is the radius of the Earth.
G and mEarth are on both sides and cancel. So,
mMoon/r12 = mstudent/rEarth2
Now, it's just algebra. Rearranging...
r12 = (rEarth)2(mMoon)/(mstudent)
and substituting the numbers will give us the answer.