I assume f (x + k) - f(x / k) is asked,
= m(x + k) + k - m(x / k) - k
= mx + mk - mx / k
= m{[1 + (1 / k)]x + k}
Solution 2:
if [f(x + k) - f(x)] / k is asked,
= {[m(x + k) + k] - [m(x) + k]} / k
= (mx + mk + k - mx - k) / k
= mk / k
= m
Pam J.
asked 09/11/19I assume f (x + k) - f(x / k) is asked,
= m(x + k) + k - m(x / k) - k
= mx + mk - mx / k
= m{[1 + (1 / k)]x + k}
Solution 2:
if [f(x + k) - f(x)] / k is asked,
= {[m(x + k) + k] - [m(x) + k]} / k
= (mx + mk + k - mx - k) / k
= mk / k
= m
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Pam J.
Clarification: Everything after “find” is supposed to be divided by k09/11/19