1) He run from 35th m to 67th m and from 7th sec to 11th sec with max speed, so his max speed is,
Vmax = (67 - 35) / (11 - 7) = 8 m/s
2)if he runs 2 sec more with max speed,
Distance1 = 2 s * 8 m/s = 16 m
3) at 7th sec, where he started to run at max speed, he is 35 m from the starting line speed. so 9th sec is 2 sec later from that instant, and we already calculated how far he runs in 2 sec at max speed at (2) which is 16 m. So,
Distance2 = 35 m + 16 m = 51 m
4) At 8.5 sec means first 7 sec (35m) plus 1.5 sec at max speed. So,
Distance3 = 35 m + 8 m/s * 1.5 s = 35 + 12 = 47 m