Denise G. answered 09/11/19
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
Problems 1 and 2 are the same.
1. Possible zeros are: Factors of 9/factors of 1 = ±1,±3,±9
It can be solved by factoring (x2-9)(x2-1) = (x+3)(x-3)(x+1)(x-1)
Solving we get the zeros: -3,3,-1,1
2. Possible zeros are: Factors of 2/Factors of 3 = ±2,±2/3,±1,±1/3
We can test using synthetic division or graphing and find the actual zeros: -1,1/3,2