Height and Velocity

Question

If an archer shoots an arrow straight upward with an initial velocity of

128128

​ft/sec from a height of

55

​ft, then its height above the ground in feet at time t in seconds is given by the function

h left parenthesis t right parenthesis equals negative 16 t squared plus 128 t plus 5h(t)=−16t2+128t+5

Answer 1

Assuming initial velocity is 128 ft/s upward and initial height is 5 ft,

then the equation shown: h(t) = -16 t² + 128 t + 5 is correct.

Is that your question or do you need to do something with this equation?