
William W. answered 09/03/19
Math and science made easy - learn from a retired engineer
The easiest way to answer these questions would be to have a function where mosquitoes are a function of raccoons. To get that, we simply combine the functions we have. Since m(p) = 50,000 - 45p and p(r) = 750 - 3.75r we can just plug in "750 - 3.75r" into the first function wherever we see a "p". That makes
m(r) = 50,000 - 45(750 - 3.75r)
m(r) = 50,000 - 33750 + 168.75r
m(r) = 16,200 + 168.75r
So if there are 200 raccoons, there are 16,200 + 168.75(200) or 50,000 mosquitoes
If there are r raccoons, then there are 16,200 + 168.75r mosquitoes
If we want no more than 36,500 mosquitoes, we plug that in and calculate the associated number of raccoons.
36,500 = 16,200 + 168.75r
20,300 = 168.75r
r = 120.3
Of course, we can't have 0.3 of a raccoon so we must have 120 raccoons or less to keep the population of mosquitoes to a max of 36,500