William W. answered 09/02/19
Experienced Tutor and Retired Engineer
Using the kinematic equation of motion:
xf = xi + vit + ½ at2
where xi = 0 and vi = 0 (because you can start your frame of reference from where the object is dropped and the object is indeed just dropped so it starts with zero velocity)
So, that reduces the equation to:
xf = ½ at2 or solving for acceleration, a = 2xf/t2
xf = -12m because you drop the object and it ends up 12m below you and t = 1.36s so:
a = 2(-12)/1.362 = -12.976 m/s2. Since the givens have at most 2 significant figures, we round the answer to -13 m/s2 (note that the negative sign just means that the acceleration due to gravity is down)