Barbara F. answered 08/30/19
Masters and Bachelors in Physics + 4 years of Engineering Experience
Hi Mulolanji!
This is a very good question, and it's complex, because we don't know the ion:
The electronic configuration for Ni (the neutral one):
1s2 2s2 2p6 3s2 3p6 3d8 4s2
This reduces to:
[Ar] 4s2 3d8
The electronic configuration for Ni2+ (the first ion):
1s2 2s2 2p6 3s2 3p6 3d8
This reduces to:
[Ar] 3d8
The electronic configuration for Ni3+ (the second ion):
1s2 2s2 2p6 3s2 3p6 3d7
This reduces to:
[Ar] 3d7
The orbital diagram for Ni:
| ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓↑↓↑↓↑_↑_ |
1s2 2s2 2p6 2s2 3p6 4s2 3d8
The orbital diagram for Ni2+:
| ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓↑↓↑↓↑_↑_ |
1s2 2s2 2p6 2s2 3p6 3d8
The orbital diagram for Ni3+:
| ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓↑↓↑_↑_↑_ |
1s2 2s2 2p6 2s2 3p6 3d7