Hello Hector,

I assume that you want to find the equation of the line that passes through the point (1,-3) and has x-intercept -1. (If this is not what you actually needed to find, let me know.)

The problem indicates that the x-intercept = -1, which is the same as saying the line contains the point (-1,0). Now we can use the two points (1,-3) and (-1,0) to find the slope.

**m = (y**_{2}** - y**_{1}**)/(x**_{2}** - x**_{1}**)**

m = (0 - (-3))/((-1 - 1)

m = 3/(-2) =** -3/2**

Now use the point-slope form to find an equation of the line.

**y - y**_{1}** = m(x - x**_{1}**)**

y - (-3) = (-3/2)(x - 1)

Generally, we prefer to express the final answer in either slope-intercept form (**y = mx + b** form), or standard form (Ax + By = C). To put the equation in slope-intercept form, we solve the above for y.

y + 3 = (-3/2)x + 3/2

y + 3 - 3 = (-3/2)x + 3/2 - 3

**y = (-3/2)x - 3/2**

Hope that helps!

William