A straight line y =mx +c passes through the point (o,k)and (h,2k).express m and c in terms of h and k.

Answer 1

y = mx + c

Where m = slope and c is y-intercept (the point where x=0)

m = ( (2k-k)/(h-0) ) [This is the slope]

m = k/h

y = ( (2k-k)/(h-0) )x + c [Use the two points to compute slope]

k = (k/h)(0) + c [The y-intercept point that was given]

c = k

Answer 2

I'm going to assume that your first point (o,k) is intended to be the number 0 and not the letter 'o'...

In slope intercept form (y = mx + c) m represents the slope of the line and c is the y-intercept. To determine the slope, m, just remember "rise over run". That is, given any 2 coordinate points (x,y), the slope is going to be the difference between the y values (rise) divided by the difference between the x values (run). For example,

m = (2k - k)/(h - 0) = k/h

Now to get the y-intercept, c, we just need to know that the y-intercept is the point on the line where x=0. Luckily we are told that the line passes through the point (x=0,y=k)! So, the y-intercept is

c = k