Denise G. answered 08/07/19
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
I would start out by factoring this as a first step, that helps solve for the zeros.
Factored form: (x2+16)(x2+16)
To find the zero, set each factor equal to zero and solve. Since they are both the same, this only needs to be done once.
x2+16 = 0 Subtract 16 from both sides
x2 = -16 Take the square root of both sides
x = ±4i are the zeros. There are 4 complex zeros, each has a multiplicity of 2 due to the fact that the factors are the same.