Calculate the ratio of Sin B

Question

  B | \

     |    \ 

     |       \
10 |         \     15

     |           \

     |_             \

  A |_|________\ C

Answer 1

since its  right angle triangle    we can find AC=  Sq( BC^2-AB^2)    ----- SQ-square root 

 

 AC = Sq(15^2 - 10^2)=Sq(225-100)=Sq(125)-->  

 

you can write  125 as multiples of 5 = Sq(5*5*5)=Sq(5^2)Sq(5)= 5 Sq5

 

Sin B = opposite/hypotenuse

        = 5(Sq5)/15= Sq(5)/3